一罐头食品净重425g,每g含Z=10℃,D118=4.7min芽孢10个,如要求成品腐败率不大于0.05%,求:F0,F118和D121值。
正确答案:
a=425*10=4250,b=0.0005
F118=D118(lga-lgb)=4.7*lg(4250/0.0005)=32.6min
F0=F118*lg-1【(118-121)/Z】=16.3min
D121.1=F0/(lga-lgb)=16.3/6.93=2.35min
F118=D118(lga-lgb)=4.7*lg(4250/0.0005)=32.6min
F0=F118*lg-1【(118-121)/Z】=16.3min
D121.1=F0/(lga-lgb)=16.3/6.93=2.35min
答案解析:有
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