一标准直齿圆柱齿轮,其模数m=2,齿数z=28,试计算齿轮的分度圆直径d、齿距p、齿根圆直径df和齿顶圆直径da和基圆半径db。(cos20°=0.94)
正确答案:
分度圆d = mz=56mm 齿距P =πm=6.28mm
齿根圆df = m(z -2.5)=51mm 齿顶圆da =m(z+2)=60mm
基圆db=mzcosα=105.24mm
齿根圆df = m(z -2.5)=51mm 齿顶圆da =m(z+2)=60mm
基圆db=mzcosα=105.24mm
答案解析:有

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