饱和水蒸气在高度l=1.5m的竖管外表面上作层流膜状凝结。水蒸气压力为p=2.5×105pa,管子表面温度为123℃。试利用努塞尔分析解计算离开管顶为0.1m、0.2m、0.4m、0.6m及1.0m处的液膜厚度和局部表面传热系数。
正确答案:
![](https://img.274949.com/Images/2020-04/04/8lfv4qne.jpg)
![](https://img.274949.com/Images/2020-04/04/7mykrxsi.jpg)
![](https://img.274949.com/Images/2020-04/04/8lfv4qne.jpg)
![](https://img.274949.com/Images/2020-04/04/7mykrxsi.jpg)
![](https://img.274949.com/Images/2020-04/04/h7brp6go.jpg)
答案解析:有
![](/editor/images/201705/qrcode_for_gh_573e2a458573_258.jpg)
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饱和水蒸气在高度l=1.5m的竖管外表面上作层流膜状凝结。水蒸气压力为p=2.5×105pa,管子表面温度为123℃。试利用努塞尔分析解计算离开管顶为0.1m、0.2m、0.4m、0.6m及1.0m处的液膜厚度和局部表面传热系数。
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