已知条件:400mm窄带钢精轧机,支撑辊直径400mm,辊颈直径d为260mm,辊身长度l为400mm,轧辊弹性模量E为22×104MPa,轧辊剪切模量G为8.1×104MPa,支撑辊轴承中心线间的距离a为965mm,支撑辊辊身边缘至轴承中心线间的距离e为278mm,轧制力P为1500Kn.求支撑辊的挠度。
正确答案:
支撑辊弯曲挠度为:
f弯=P,
带入具体数据,得f弯=0.1809mm
支撑辊弯曲挠度为:
f剪=
,带入具体数据,得f剪=0.0558mm
所以,支撑辊挠度为:F=f弯+f剪=0.1809+0.0558=0.2367mm
f弯=P,
![](https://www.274949.com/images/2020-03/07/g335j32e.jpg)
支撑辊弯曲挠度为:
f剪=
![](https://www.274949.com/images/2020-03/07/n21ooyau.jpg)
所以,支撑辊挠度为:F=f弯+f剪=0.1809+0.0558=0.2367mm
答案解析:有
![](/editor/images/201705/qrcode_for_gh_573e2a458573_258.jpg)
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