某油罐有含油1.92%的不合格蜡油57吨,用含油1.3%的合格蜡油104吨调和,调和后的含油多少?
正确答案:
含油量={(含油A³吨数A+含油B³吨数B./吨数A+吨数B}³100%
={(1.92%³57+1.3%³104)/57+104}³100%=1.52%
={(1.92%³57+1.3%³104)/57+104}³100%=1.52%
答案解析:有
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某油罐有含油1.92%的不合格蜡油57吨,用含油1.3%的合格蜡油104吨调和,调和后的含油多少?
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