已知u=36sin(ωt+π/4)伏,i=6sin(ωt+π/6)安,求μ和i的初相位和u和i的相位差,并指出哪个超前?哪个滞后?
正确答案:
u的初相位φ=π/4=45°
i的初相位φ=π/6=30°
相位差φ=φ-φ=45°-30°=15°
故u超前i15°,或者说i滞后u15°
i的初相位φ=π/6=30°
相位差φ=φ-φ=45°-30°=15°
故u超前i15°,或者说i滞后u15°
答案解析:有
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已知u=36sin(ωt+π/4)伏,i=6sin(ωt+π/6)安,求μ和i的初相位和u和i的相位差,并指出哪个超前?哪个滞后?
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