public class TwoThreads {  private static Object resource = new Object（）；  private static void delay（long n） {  try { Thread.sleep（n）； }  catch （Exception e） { System.out.print（”Error “）； }  }  public static void main（String[] args） {  System.out.print（”StartMain “）；  new Thread1（）.start（）；  delay（1000）；  Thread t2 = new Thread2（）；  t2.start（）；  delay（1000）；  t2.interrupt  delay（1000）；  System.out.print（”EndMain “）；  }  static class Thread 1 extends Thread {  public void run（） {  synchronized （resource） {  System.out.print（”Startl “）；  delay（6000）；  System.out.print（”End1 “）；  }  }  }  static class Thread2 extends Thread {  public void run（） {  synchronized （resource） {  System.out.print（”Start2 “）；  delay（2000）；  System.out.print（”End2 “）；  }  }  }  }  Assume that sleep（n） executes in exactly m milliseconds， and all other code executes in an insignificant amount of time. What is the output if the main（） method is run？（） 

• A、 Compilation fails.
• B、 Deadlock occurs.
• C、 StartMain Start1 Error EndMain End1
• D、 StartMain Start1 EndMain End1 Start2 End2
• E、 StartMain Start1 Error Start2 EndMain End2 End1
• F、StartMain Start1 EndMain End1 Start2 Error End2