往0.3582g含CaCO3及不与酸左洋杂质的石灰石里加入25.00mL0.1471mol/L溶液，过量的酸需用10.15mLNaOH溶液回滴。已知1mLNaOH溶液相当于1.032mLHCl溶液。求石灰石的纯度及CO2的质量分数。（CaCO3：100.1；CO2：44.01）
正确答案:
2HCl+CaCO3=CaCl2+H2O+CO2
CaCO3%=[1/2（0.02500-10.15x10-3x1.032）x0.1471x100.1]/0.3582]x100%=29.85%
CO2%=[1/2（0.02500-10.15x10-3x1.032）x0.1471x44.01]/0.3582]x100%=13.12%
CaCO3%=[1/2（0.02500-10.15x10-3x1.032）x0.1471x100.1]/0.3582]x100%=29.85%
CO2%=[1/2（0.02500-10.15x10-3x1.032）x0.1471x44.01]/0.3582]x100%=13.12%
答案解析:有
微信扫一扫手机做题