计算题：用负压筛测定某水泥细度时，已知过筛前水泥连称样盘重量是36.9g，过筛后筛余连称样盘重量是14.9g，称样盘重14.3g，负压筛的校正系数是0.97，则该水泥的细度是多少？
正确答案:
解：（14.9-14.3）÷（36.9-14.3）×0.97×100%=2.6%
已知某厂熟料化学成分为：SiO2：21.98%、Al2O3：6.12%、Fe2O3：4.31%、CaO：65.80%MgO：1.02%，计算其矿物组成（IM＞0.64）。
C3S＝4.07C－7.60S－6.72A－1.43F
=4.07×65.80%－7.60×21.98%－6.72×6.12%－1.43×4.31%
=53.47%
C2S＝2.87S－0.754C3S
=2.87×21.98%－0.754×53.47%
=22.77%
C3A＝2.65A－1.69F
=2.65×6.12%－1.69×4.31%
=8.95%
C4AF＝3.04F
=3.04×4.31%
=13.10%
已知某厂熟料化学成分为：SiO2：21.98%、Al2O3：6.12%、Fe2O3：4.31%、CaO：65.80%MgO：1.02%，计算其矿物组成（IM＞0.64）。
C3S＝4.07C－7.60S－6.72A－1.43F
=4.07×65.80%－7.60×21.98%－6.72×6.12%－1.43×4.31%
=53.47%
C2S＝2.87S－0.754C3S
=2.87×21.98%－0.754×53.47%
=22.77%
C3A＝2.65A－1.69F
=2.65×6.12%－1.69×4.31%
=8.95%
C4AF＝3.04F
=3.04×4.31%
=13.10%
答案解析:有
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